Optimal. Leaf size=193 \[ -\frac{b (a+b \tan (c+d x))^{n+1} \, _2F_1\left (1,n+1;n+2;\frac{a+b \tan (c+d x)}{a-\sqrt{-b^2}}\right )}{2 \sqrt{-b^2} d (n+1) \left (a-\sqrt{-b^2}\right )}+\frac{b (a+b \tan (c+d x))^{n+1} \, _2F_1\left (1,n+1;n+2;\frac{a+b \tan (c+d x)}{a+\sqrt{-b^2}}\right )}{2 \sqrt{-b^2} d (n+1) \left (a+\sqrt{-b^2}\right )}+\frac{(a+b \tan (c+d x))^{n+1}}{b d (n+1)} \]
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Rubi [A] time = 0.148413, antiderivative size = 193, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {3543, 3485, 712, 68} \[ -\frac{b (a+b \tan (c+d x))^{n+1} \, _2F_1\left (1,n+1;n+2;\frac{a+b \tan (c+d x)}{a-\sqrt{-b^2}}\right )}{2 \sqrt{-b^2} d (n+1) \left (a-\sqrt{-b^2}\right )}+\frac{b (a+b \tan (c+d x))^{n+1} \, _2F_1\left (1,n+1;n+2;\frac{a+b \tan (c+d x)}{a+\sqrt{-b^2}}\right )}{2 \sqrt{-b^2} d (n+1) \left (a+\sqrt{-b^2}\right )}+\frac{(a+b \tan (c+d x))^{n+1}}{b d (n+1)} \]
Antiderivative was successfully verified.
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Rule 3543
Rule 3485
Rule 712
Rule 68
Rubi steps
\begin{align*} \int \tan ^2(c+d x) (a+b \tan (c+d x))^n \, dx &=\frac{(a+b \tan (c+d x))^{1+n}}{b d (1+n)}-\int (a+b \tan (c+d x))^n \, dx\\ &=\frac{(a+b \tan (c+d x))^{1+n}}{b d (1+n)}-\frac{b \operatorname{Subst}\left (\int \frac{(a+x)^n}{b^2+x^2} \, dx,x,b \tan (c+d x)\right )}{d}\\ &=\frac{(a+b \tan (c+d x))^{1+n}}{b d (1+n)}-\frac{b \operatorname{Subst}\left (\int \left (\frac{\sqrt{-b^2} (a+x)^n}{2 b^2 \left (\sqrt{-b^2}-x\right )}+\frac{\sqrt{-b^2} (a+x)^n}{2 b^2 \left (\sqrt{-b^2}+x\right )}\right ) \, dx,x,b \tan (c+d x)\right )}{d}\\ &=\frac{(a+b \tan (c+d x))^{1+n}}{b d (1+n)}+\frac{b \operatorname{Subst}\left (\int \frac{(a+x)^n}{\sqrt{-b^2}-x} \, dx,x,b \tan (c+d x)\right )}{2 \sqrt{-b^2} d}+\frac{b \operatorname{Subst}\left (\int \frac{(a+x)^n}{\sqrt{-b^2}+x} \, dx,x,b \tan (c+d x)\right )}{2 \sqrt{-b^2} d}\\ &=\frac{(a+b \tan (c+d x))^{1+n}}{b d (1+n)}-\frac{b \, _2F_1\left (1,1+n;2+n;\frac{a+b \tan (c+d x)}{a-\sqrt{-b^2}}\right ) (a+b \tan (c+d x))^{1+n}}{2 \sqrt{-b^2} \left (a-\sqrt{-b^2}\right ) d (1+n)}+\frac{b \, _2F_1\left (1,1+n;2+n;\frac{a+b \tan (c+d x)}{a+\sqrt{-b^2}}\right ) (a+b \tan (c+d x))^{1+n}}{2 \sqrt{-b^2} \left (a+\sqrt{-b^2}\right ) d (1+n)}\\ \end{align*}
Mathematica [C] time = 0.154292, size = 138, normalized size = 0.72 \[ \frac{(a+b \tan (c+d x))^{n+1} \left (i b (a+i b) \, _2F_1\left (1,n+1;n+2;\frac{a+b \tan (c+d x)}{a-i b}\right )+(a-i b) \left (-i b \, _2F_1\left (1,n+1;n+2;\frac{a+b \tan (c+d x)}{a+i b}\right )+2 a+2 i b\right )\right )}{2 b d (n+1) (b-i a) (b+i a)} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.186, size = 0, normalized size = 0. \begin{align*} \int \left ( \tan \left ( dx+c \right ) \right ) ^{2} \left ( a+b\tan \left ( dx+c \right ) \right ) ^{n}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \tan \left (d x + c\right ) + a\right )}^{n} \tan \left (d x + c\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (b \tan \left (d x + c\right ) + a\right )}^{n} \tan \left (d x + c\right )^{2}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (a + b \tan{\left (c + d x \right )}\right )^{n} \tan ^{2}{\left (c + d x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \tan \left (d x + c\right ) + a\right )}^{n} \tan \left (d x + c\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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